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NEW QUESTION: 1
この構成を調べます。
1. CDB1は、Oracle Database 12cリリース2コンテナデータベース（CDB）です。
2. PDB1とPDB2は、CDB1の2つのプラガブルデータベース（PDB）です。
すべてのアップグレード前のタスクを正常に実行した後、Oracle Database18c環境から次のコマンドを実行します。
結果はどうですか？
A. PDB2がUPGRADE状態ではないため、失敗します。
B. CDB $ ROOT、PDB $ SEED、およびPDB2のみがアップグレードされます。
C. CDB $ ROOTとPDB $ SEEDのみがアップグレードされます。
D. CDB $ ROOT、PDB $ SEED、およびPDB1のみがアップグレードされます。
E. PDB $ SEEDがMIGRATE状態であるため、失敗します。
F. CDB $ ROOT、PDB $ SEED、PDB1、およびPDB2がアップグレードされます。
Answer: C
NEW QUESTION: 2
Which two options are ways in which an OSPFv3 router handles hello packets with a clear address-family bit? (Choose two.)
A. IPv4 unicast packets are discarded.
B. IPv6 unicast packets are forwarded.
C. IPv4 unicast packets are forwarded.
D. IPv6 unicast packets are discarded.
Answer: A,B
Explanation:
Explanation/Reference:
Explanation:
A typical distance vector protocol saves the following information when computing the best path to a destination: the distance (total metric or distance, such as hop count) and the vector (the next hop). For instance, all the routers in the network in Figure 1 are running Routing Information Protocol (RIP). Router Two chooses the path to Network A by examining the hop count through each available path.
Since the path through Router Three is three hops, and the path through Router One is two hops, Router Two chooses the path through One and discards the information it learned through Three. If the path between Router One and Network A goes down, Router Two loses all connectivity with this destination until it times out the route of its routing table (three update periods, or 90 seconds), and Router Three re- advertises the route (which occurs every 30 seconds in RIP). Not including any hold-down time, it will take between 90 and 120 seconds for Router Two to switch the path from Router One to Router Three.
EIGRP, instead of counting on full periodic updates to re-converge, builds a topology table from each of its neighbor's advertisements (rather than discarding the data), and converges by either looking for a likely loop-free route in the topology table, or, if it knows of no other route, by querying its neighbors. Router Two saves the information it received from both Routers One and Three. It chooses the path through One as its best path (the successor) and the path through Three as a loop-free path (a feasible successor). When the path through Router One becomes unavailable, Router Two examines its topology table and, finding a feasible successor, begins using the path through Three immediately.
Reference: http://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routing- protocol- eigrp/16406-eigrp-toc.html
NEW QUESTION: 3
In solicitation planning activity of Contract Management Process, what will be the input by using standard forms as a tool and whose output will be procurements documents?
A. Procurement management plan
B. Market conditions
C. Work results
D. Qualified seller list
Answer: A