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NEW QUESTION: 1
An administrator has an environment with these conditions and requirements:
* The host provides 6GHz of CPU and 32GB of memory
* The host is shared between the Marketing and QA departments
* The QA department needs a higher compute resource priority
How can the administrator meet the conditions and requirements?
A. Create a resource pool for each department and use the Shares attribute to prioritize the allocation of resources.
B. Assign affinity or anti-affinity rules to the appropriate VMs for each department.
C. Adjust NIOC or SIOC as appropriate to give the QA department a higher compute priority within the cluster.
D. Set the VM priority to high for QA department VMs and normal for Marketing department VMs.
Answer: A

NEW QUESTION: 2
Which command will activate the statement concentrator?
A. UPDATE DB CFG FOR mydb USING STMT_CONC YES
B. UPDATE DB CFG FOR mydb USING STMT_CONC LITERALS
C. UPDATE DB CFG FOR mydb USING STMTCONCENT ON
D. UPDATE DB CFG FOR mydb USING STMTCONC ENABLED
Answer: B

NEW QUESTION: 3
Consider the entity-relation (ER) diagram shown in the exhibit. When the logical database design phase is completed, which of the following is a valid DBDL description of the base relations for the ER diagram?

A. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
STU_CLASS(
Student_Number: integer NOT NULL
Class_Num: integer NOT NULL)
Primary Key Student_Number
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
B. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
Foreign Key Class_Num References STUDENT
C. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
D. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
STU_CLASS(
Student_Number: integer NOT NULL
Class_Num: integer NOT NULL)
Primary Key Student_Number, Class_Num
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
Answer: D