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NEW QUESTION: 1
ネットワーク管理者は、会社がDDoS攻撃を受けていることを技術者に通知します。いくつかの内部Windows PCがトラフィックのソースです。ネットワーク管理者は、技術者にWindowsコンピューター名を提供し、それらをすぐにスキャンしてクリーンアップすることを伝えます。 PCが感染する可能性が最も高いのは、次のどのタイプの感染ですか? (2つ選択してください。)
A. スパイウェア
B. ランサムウェア
C. ワーム
D. ウイルス
E. ゾンビ
F. ボットネット
Answer: C,E

NEW QUESTION: 2
Outgoing foreign transactions of similar amounts trigger a monitoring alert for a customer's accounts. During the evaluation of the accounts, the bank discovers the wire transfers were very small amounts and occurred within the last 3 months following a long period of inactivity. The wire transfers appear to originate from legal sources. To assess the potential of terrorist financing, the institution must ensure the:
A. beneficiaries of transfers are not on a terrorist watch list.
B. beneficiaries of transfers are not included on the Transparency International List.
C. account holder presents proof the funds are legal.
D. account holder does not reside in a country included on the U.S. State Department State Sponsors of Terrorism List.
Answer: A

NEW QUESTION: 3
The sponsors of a well-known charity came up with a unique idea to attract wealthy patrons to the
$ 500 a plate dinner. After the dinner, it was announced that each patron attending could buy a set of 20 tickets for the gaming tables. The chance of winning a prize for each of the 20 plays is 50-50. If you bought a set of 20 tickets, what is the chance that you will win 15 or more prizes?
A. 0.006
B. 0.250
C. 0.021
Answer: C
Explanation:
This is a binomial probability. The probability of getting r successes out of n trials where the probability of success each trial is p and probability of failure each trial is q (where q = 1-p) is given by:
r (n-r)
n!(p )[q ]/r!(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have
15 5
P(15) = 20!(0.5 )(0.5 )/15!5! = 0.0148
16 4
P(16) = 20!(0.5 )(0.5 )/16!4! = 0.0046 P(17) = 0.0011 P(18) = 0.0002 P(19) = 0.00002 P(20) = 0.000001
The sum adds up to 0.0207.