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NEW QUESTION: 1
Your company will soon start moving critical systems Into Oracle Cloud Infrastructure (OCI) platform. These systems will reside in the us-phoenix-1and us-ashburn 1 regions. As part of the migration planning, you are reviewing the company's existing security policies and written guidelines for the OCI platform usage within the company. you have to work with the company managed key.
Which two options ensure compliance with this policy?
A. When you create a new compute instance through OCI console, you use the default options for "configure boot volume" to speed up the process to create this compute instance.
B. When you create a new block volume through OCI console, select Encrypt using Key Management checkbox and use encryption keys generated and stored in OCI Key Management Service.
C. When you create a new compute instance through OCI console, you use the default shape to speed up the process to create this compute instance.
D. When you create a new OCI Object Storage bucket through OCI console, you need to choose "ENCRYPT USING CUSTOMER-MANAGED KEYS" option.
E. You do not need to perform any additional actions because the OCI Block Volume service always encrypts all block volumes, boot volumes, and volume backups at rest by using the Advanced Encryption Standard (AES) algorithm with 256-bit encryption.
Answer: B,D
Explanation:
Block Volume Encryption
By default all volumes and their backups are encrypted using the Oracle-provided encryption keys. Each time a volume is cloned or restored from a backup the volume is assigned a new unique encryption key.
You have the option to encrypt all of your volumes and their backups using the keys that you own and manage using the Vault service.If you do not configure a volume to use the Vault service or you later unassign a key from the volume, the Block Volume service uses the Oracle-provided encryption key instead.
This applies to both encryption at-rest and in-transit encryption.
Object Storage Encryption
Object Storage employs 256-bit Advanced Encryption Standard (AES-256) to encrypt object data on the server. Each object is encrypted with its own data encryption key. Data encryption keys are always encrypted with a master encryption key that is assigned to the bucket. Encryption is enabled by default and cannot be turned off. By default, Oracle manages the master encryption key. However, you can optionally configure a bucket so that it's assigned an Oracle Cloud Infrastructure Vault master encryption key that you control and rotate on your own schedule.
Encryption: Buckets are encrypted with keys managed by Oracle by default, but you can optionally encrypt the data in this bucket using your own Vault encryption key. To use Vault for your encryption needs, select Encrypt Using Customer-Managed Keys. Then, select the Vault Compartment and Vault that contain the master encryption key you want to use. Also select the Master Encryption Key Compartment and Master Encryption Key.
NEW QUESTION: 2
Proper positioning for the child who is in Bryant's traction is:
A. Both hips and knees maintained at a 90-degree flexion angle, and the back flat on the bed
B. Both hips flexed at a 90-degree angle with the knees extended and the buttocks elevated off the bed
C. Both legs extended, and the hips are not flexed
D. The affected leg extended with slight hip flexion
Answer: B
Explanation:
Explanation/Reference:
Explanation:
(A) The child's weight supplies the countertraction for Bryant's traction; the buttocks are slightly elevated off the bed, and the hips are flexed at a 90-degree angle. Both legs are suspended by skin traction. (B) The child in Buck's extension traction maintains the legs extended and parallel to the bed. (C) The child in Russell traction maintains hip flexion of the affected leg at the prescribed angle with the leg extended. (D) The child in "90-90" traction maintains both hips and knees at a 90-degree flexion angle and the back is flat on the bed.
NEW QUESTION: 3
The voice band is commonly called:
A. 8 kilohertz wide.
B. A 32-Mbps band.
C. A 4-kilohertz band.
D. 1.544 Mbps wide.
Answer: C