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NEW QUESTION: 1
You work as a Database Designer for Tritech Inc. You are designing a table named Info. The table contains the following attributes:
Login and Password
Name
ContactNumber
Address
Each new employee joining the company is assigned an E-mail Login and Password. This E-mail Login and Password is used by each employee to access his account on the company's Web site. The value of both the attributes should be unique and cannot be NULL. You design an artificial key EmpID in the Info table to serve as a primary key. Which of the following factors lead you to define an artificial key for use as a primary key in the Info table?
Each correct answer represents a part of the solution. Choose all that apply.
A. The value of the primary key must be persistent.
B. The value of the primary key cannot be NULL.
C. The natural key contains highly sensitive data.
D. The value of the primary key must be unique.
Answer: A,B,C,D
Explanation:
The Name attribute cannot be used as a primary key, as two employees may have the same name in a company. For an attribute to be used as a primary key, it must have a unique value.The primary key attribute cannot contain NULL values. ContactNumber cannot be used as a primary key, for it is possible that some employees in the company may not have a ContactNumber, which will result in NULL values of ContactNumber for such employees. To be used as a primary key, a natural key must contain a unique value. This is a prerequisite for a primary key. In addition to this, if the natural key contains sensitive data, it cannot be used as a primary key. The primary key must be persistent, i.e. the value of the attribute must remain the same throughout the lifetime of the instance. Therefore, Address cannot be used as a primary key, as it is possible that an employee might change his house in future and this may lead to a change in the value of the attribute. In the given scenario, Login and Password of each employee is unique and cannot be NULL, but sharing this information with others is not at all appropriate, as these are classified as sensitive data. If one employee comes to know about the login and password of another employee, he can access his mail account and read his confidential mails or even send mails from his account to other people. Therefore, all these factors lead you to define an artificial key.

NEW QUESTION: 2
Drag the component on the left to the TCP/IP layer it corresponds to on the right. Not all options are used.

Answer:
Explanation:

NEW QUESTION: 3
すべての認証イベントが正しく処理されるように、LoginEvent.csのLE03行にコードを挿入する必要があります。
どのようにしてコードを完成させるべきですか？回答するには、回答領域で適切なオプションを選択します。
注：それぞれ正しい選択は1ポイントの価値があります。

Answer:
Explanation:

Explanation:
Box 1: id
id is a unique identifier for the event.
Box 2: eventType
eventType is one of the registered event types for this event source.
Box 3: dataVersion
dataVersion is the schema version of the data object. The publisher defines the schema version.
Scenario: Authentication events are used to monitor users signing in and signing out. All authentication events must be processed by Policy service. Sign outs must be processed as quickly as possible.
The following example shows the properties that are used by all event publishers:
[
{
"topic": string,
"subject": string,
"id": string,
"eventType": string,
"eventTime": string,
"data":{
object-unique-to-each-publisher
},
"dataVersion": string,
"metadataVersion": string
}
]
References:
https://docs.microsoft.com/en-us/azure/event-grid/event-schema