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NEW QUESTION: 1
Which Dual stack preferred protocol when configured?
A. IPV6
B. IPX
C. IPV4
Answer: A

NEW QUESTION: 2
This tool is an 802.11 WEP and WPA-PSK keys cracking program that can recover keys once enough data packets have been captured. It implements the standard FMS attack along with some optimizations like KoreK attacks, as well as the PTW attack, thus making the attack much faster compared to other WEP cracking tools.
Which of the following tools is being described?
A. Airguard
B. Aircrack-ng
C. WLAN-crack
D. wificracker
Answer: B
Explanation:
Explanation
Aircrack-ng is a complete suite of tools to assess WiFi network security.
The default cracking method of Aircrack-ng is PTW, but Aircrack-ng can also use the FMS/KoreK method, which incorporates various statistical attacks to discover the WEP key and uses these in combination with brute forcing.
References:
http://www.aircrack-ng.org/doku.php?id=aircrack-ng

NEW QUESTION: 3
Para Co. is reviewing the following data relating to an energy saving investment proposal:

What would be the annual savings needed to make the investment realize a 12% yield?
A. $13,889
B. $11,111
C. $12,306
D. $8,189
Answer: C
Explanation:
Choice "c" is correct. The annual savings needed to make the investment realize a 12% yield is where the
present value of the cash savings/inflows equals the present value of the net cash outflows. Use algebra
to calculate the annual savings, as follows:

Choice "a" is incorrect. The annual savings needed to make the investment realize a 12% yield is where
the present value of the cash savings/inflows equal the present value of the net cash outflows.
Choice "b" is incorrect. Subtract the present value of $10,000 due in 5 years at 12%, or $10,000 * .57 =
$ 5,700. Don't subtract the entire $10,000.
Choice "d" is incorrect. Subtract the present value of the $10,000 residual value from the $50,000 cost.

NEW QUESTION: 4



A. Corp-1
B. Branch-2
C. Branch-1
D. Corp-3
E. Corp-2
F. Corp-4
Answer: B,F
Explanation:
There are 2 segments on the topology above which are separated by Corp-3 router. Each
segment will have a DR so we have 2 DRs.
To select which router will become DR they will compare their router-IDs. The router with highest
(best) router-ID will become DR. The router-ID is chosen in the order below:
+
The highest IP address assigned to a loopback (logical) interface.
+
If a loopback interface is not defined, the highest IP address of all active router's physical interfaces will be chosen.
In this question, the IP addresses of loopback interfaces are not mentioned so we will consider IP addresses of all active router's physical interfaces. Router Corp-4 (10.1.40.40) & Branch-2
(10.2.20.20) have highest "active" IP addresses so they will become DRs.