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NEW QUESTION: 1
A. Option A
B. Option D
C. Option B
D. Option C
Answer: C,D
NEW QUESTION: 2
モビリティコントローラー（MC）のネットワークは、モビリティマスター（MM）によって管理されます。管理者がMCのIPアドレスを誤って設定し、MCがMMへの接続を失います。
管理者はこの問題をどのように修正すればよいですか？
A. モビリティマスターで災害復旧モードを使用します。
B. モビリティマスターで自動リカバリモードを使用します。
C. モビリティコントローラーで災害復旧モードを使用します。
D. モビリティマスターで以前の構成を復元します。
Answer: C
NEW QUESTION: 3
Scenario: A Citrix Administrator needs to deploy Receiver to a group of new users who use restricted workstations that do NOT allow applications to be installed locally on them. These users are internal to the company and connect directly to the XenDesktop environment via Storefront.
Which deployment option is optimal for these new users?
A. Receiver for Web deployed from StoreFront
B. Native Receiver deployed through Active Directory scripting
C. Receiver for HTML5 deployed through client web browser
D. Native Receiver deployed through group policy
Answer: A
NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:
You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: C
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php