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NEW QUESTION: 1
What is the correct sequence of operations for configuring Clone action in NetWorker?
Answer:
Explanation:
NEW QUESTION: 2
次の表に示すユーザーを含むMicrosoft Azureアクティビティディレクトリ（Azure AD）テナントがあります。
Group3はGroup1のメンバーです。
会社はWindows Defender Advanced Threat Protection（ATP）を使用しています。 Windows Defender ATPには、次の表に示す役割が含まれています。
Windows Defender ATPには、次の表に示すデバイスグループが含まれています。
以下の各ステートメントについて、ステートメントが真である場合は「はい」を選択します。それ以外の場合は、「いいえ」を選択します。
注：それぞれの正しい選択には1ポイントの価値があります。
Answer:
Explanation:
Explanation
NEW QUESTION: 3
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 4-bit code words x 8 kHz
B. 2 x 8 kHz x 4-bit code words
C. 2 x 4 kHz x 8-bit code words
D. 8 kHz x 8-bit code words
Answer: C
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400 Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz. According to Nyquist
theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps
(notice about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit
per second = 64 Kilobit per second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling
frequency must be greater than twice the bandwidth of the input signal in order to be able
to reconstruct the original perfectly from the sampled version."