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NEW QUESTION: 1
ネットワーク管理者は、会社がDDoS攻撃を受けていることを技術者に通知します。いくつかの内部Windows PCがトラフィックのソースです。ネットワーク管理者は、技術者にWindowsコンピューター名を提供し、それらをすぐにスキャンしてクリーンアップすることを伝えます。 PCが感染する可能性が最も高いのは、次のどのタイプの感染ですか？ （2つ選択してください。）
A. ウイルス
B. ボットネット
C. ゾンビ
D. ワーム
E. ランサムウェア
F. スパイウェア
Answer: C,D
NEW QUESTION: 2
Outgoing foreign transactions of similar amounts trigger a monitoring alert for a customer's accounts. During the evaluation of the accounts, the bank discovers the wire transfers were very small amounts and occurred within the last 3 months following a long period of inactivity. The wire transfers appear to originate from legal sources. To assess the potential of terrorist financing, the institution must ensure the:
A. beneficiaries of transfers are not included on the Transparency International List.
B. account holder does not reside in a country included on the U.S. State Department State Sponsors of Terrorism List.
C. account holder presents proof the funds are legal.
D. beneficiaries of transfers are not on a terrorist watch list.
Answer: D
NEW QUESTION: 3
The sponsors of a well-known charity came up with a unique idea to attract wealthy patrons to the
$ 500 a plate dinner. After the dinner, it was announced that each patron attending could buy a set of 20 tickets for the gaming tables. The chance of winning a prize for each of the 20 plays is 50-50. If you bought a set of 20 tickets, what is the chance that you will win 15 or more prizes?
A. 0.021
B. 0.250
C. 0.006
Answer: A
Explanation:
This is a binomial probability. The probability of getting r successes out of n trials where the probability of success each trial is p and probability of failure each trial is q (where q = 1-p) is given by:
r (n-r)
n!(p )[q ]/r!(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have
15 5
P(15) = 20!(0.5 )(0.5 )/15!5! = 0.0148
16 4
P(16) = 20!(0.5 )(0.5 )/16!4! = 0.0046 P(17) = 0.0011 P(18) = 0.0002 P(19) = 0.00002 P(20) = 0.000001
The sum adds up to 0.0207.