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NEW QUESTION: 1
R1 is unable to establish an OSPF neighbor relationship with R3. What are possible reasons for this problem? (Choose two)

A. All of the routers need to be configured for backbone Area 1.
B. R1 and R2 are the DR and BDR, so OSPF will not establish neighbor adjacency with R3.
C. A static route has been configured from R1 to R3 and prevents the neighbor adjacency from being established.
D. The hello and dead interval timers are not set to the same values on R1 and R3.
E. EIGRP is also configured on these routers with a lower administrative distance.
F. R1 and R3 are configured in different areas.
Answer: D,F
Explanation:
Explanation/Reference:
Explanation:
To become OSPF neighbors, routers must meet these requirements: Hello interval, Dead interval and AREA number -> D and F are correct.

NEW QUESTION: 2
Ruby Manufacturing has 30 sales employees who will use SAP Business One in a similar way. What is the most efficient way to design general authorization permissions for the functionality required by these employees?
Please choose the correct answer.
Response:
A. Define the general authorizations needed for the role and set this role as a default in the user accounts for the sales employees
B. Define the employees as sales employees/buyers in SAP Business One. They will automatically receive the same general authorizations.
C. Assign Limited CRM license types to the sales employees. This will automatically set the general authorizations for sales employees.
D. Make a list of the modules and functions that one of the employees needs to use. Assign general authorizations to match this list, and copy the authorizations to the other users.
Answer: D

NEW QUESTION: 3
You have been asked to evaluate how EIGRP is functioning in a customer network.







What is the advertised distance for the 192.168.46.0 network on R1?
A. 0
B. 1
C. 2
D. 3
Answer: A

NEW QUESTION: 4
Which three are advantages of the Java exception mechanism?
A. Provides a set of standard exceptions that covers all the possible errors
B. Improves the program structure because the programmer can choose where to handle exceptions
C. Improves the program structure because exceptions must be handled in the method in which they occurred
D. Improves the program structure because the error handling code is separated from the
normal program function
E. allows the creation of new exceptions that are tailored to the particular program being
Answer: B,D,E
Explanation:
A: The error handling is separated from the normal program logic.
C: You have some choice where to handle the exceptions.
E: You can create your own exceptions.